counting the number of crossovers - StockFetcher.com Stock Screener

StockFetcher Forums · General Discussion · counting the number of crossovers

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se 3 posts msg #161139 - Ignore se	6/10/2024 4:57:03 PM Can StockFetcher be used to count the number times that the 8 day MA crossed over or below the 21 MA in the last 60 days, and display the number of such crossovers in a new column with add column Thanks, Steve : new to stockFetcher
nibor100 1,044 posts msg #161140 - Ignore nibor100	6/11/2024 12:17:39 PM Welcome to SF! The short answer is, Yes. So now, do you want to take a shot of writing that filter yourself, first and if it doesn't do what you want paste it here so we can take a look at it? (that is the best way to learn filter coding in SF) Ed S.
lis 37 posts msg #161141 - Ignore lis	6/11/2024 1:32:51 PM And, hint: Stockfetcher provides examples of indicators and measures, along with examples of how to use them: https://www.stockfetcher.com/forums/Indicators Count -- Occurences is one of those: https://www.stockfetcher.com/forums/Indicators/Count-Occurrences/34492
Mactheriverrat 3,157 posts msg #161143 - Ignore Mactheriverrat	6/11/2024 9:23:50 PM Submit Fetcher[ Draw ma(8) Draw ma(21) chart-time is 7 months /* m8m21 is number of consecutive days MA(8) above (+)/below(-) previous MA(21) */ set{m8m21b,days( ma(8) is above ma(21) ,250)} set{m8m21a,days( ma(8) is below ma(21) ,250)} set{m8m21, m8m21a - m8m21b} and add column m8m21 {m8m21} Set{cntm8m21a,count( MA(8) > MA(21) ,1)} draw cntm8m21a Set{cntm8m21b,count( MA(8) < MA(21),1)} draw cntm8m21b ]
wantonellis 161 posts msg #161146 - Ignore wantonellis	6/12/2024 2:08:06 PM Fetcher[ ma(8) crossed above ma(21) with the last 60 days draw ma(8) draw ma(21) set{ma_crossed, count(ma(8) crossed above ma(21),60)} add column ma_crossed set{ma_signal, count(ma(8) crossed above ma(21),1)} draw ma_signal ]
nibor100 1,044 posts msg #161150 - Ignore nibor100	6/18/2024 2:23:37 PM @se/Steve, Since you wanted a total column of both up and down crossovers, I coded the filter below borrowing from all 3 other respondents and have provided some alternative ways to display the counts. Ed S. Fetcher[ Draw ma(8) Draw ma(21) chart-time is 61 days set{8crossup21, count(MA(8) crossed above MA(21),60)} set{8crossdown21, count(MA(8) crossed below MA(21),60)} set{SumXupandXdown, 8crossup21 + 8crossdown21} add column SumXupandXdown add column 8crossup21 draw 8crossup21 add column 8crossdown21 draw 8crossdown21 set{var3, 8crossup21} draw var3 Legend{var3, 8crossesesup21} PlotType{var3,dot} draw var3 line at 0 set{var4, 8crossdown21} draw var4 Legend{var4, 8crossesdown21} PlotType{var4,dot} draw var4 line at 0 m8m21 is number of consecutive days MA(8) above (+)/below(-) previous MA(21) set{m8m21b,days( ma(8) is above ma(21) ,250)} set{m8m21a,days( ma(8) is below ma(21) ,250)} set{m8m21, m8m21a - m8m21b} and add column m8m21 {m8m21} Set{cntm8m21a,count( MA(8) > MA(21) ,1)} draw cntm8m21a Set{cntm8m21b,count( MA(8) < MA(21),1)} draw cntm8m21b sort column 5 descending draw m8m21 PlotType{m8m21,zerobar} ]

StockFetcher Forums · General Discussion · counting the number of crossovers

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